Neon Number Check in Java: Explanation & Practice
Check if a number is a Neon number
Problem summary
A Neon number equals the sum of digits of its square (e.g., 9² = 81, 8+1 = 9).
Starter code
public class Main {
public static void main(String[] args) {
int number = 9; // Test case 1
// Check if Neon number
// Print: Is Neon: <true/false>
}
}Expected output and test cases
- 9² = 81, 8+1=9
Is Neon: true
- 1² = 1, 1=1
Is Neon: true
- 5² = 25, 2+5=7≠5
Is Neon: false
Hints
- Calculate the square
- Sum all digits of the square
- Compare sum with original number
Related Control Flow exercises
- Practice Abundant Number Check in Java
- Practice Kaprekar Number Check in Java
- Practice Advanced Leap Year in Java
Practice all Control Flow exercises · Run this idea in the Java compiler